SAME BIRTHDAY PROBLEM¶

CALCULATION (USING R):¶

In [14]:
result = 1
for (i in 1:30){
p = (365-i+1)/365
result = result * p
}
1- result

Out[14]:
0.706316242719269

CONCLUSION:¶

The chance of having at least 2 students(amongs 30 students) got the same birthday is approximately 70.6%