SAME BIRTHDAY PROBLEM

image image image

CALCULATION (USING R):

In [14]:
result = 1
for (i in 1:30){
    p = (365-i+1)/365
    result = result * p
}
1- result
Out[14]:
0.706316242719269

CONCLUSION:

The chance of having at least 2 students(amongs 30 students) got the same birthday is approximately 70.6%